#!/usr/bin/env python

import pwn
import sys
import re
import binascii
import random

N = 128
_ROL_ = lambda x, i : ((x << i) | (x >> (N-i))) & (2**N - 1)
_ROR_ = lambda x, i : ((x >> i) | (x << (N-i))) & (2**N - 1)

class HashRoll:
    def __init__(self):
        self.reset_state()

    def hash_step(self, i):
        r1, r2 = self.state[2*i], self.state[2*i+1]
        r = _ROL_(self.state[-2], r1) ^ _ROL_(self.state[-1], r2)
        print(f'h{i} = {r}')
        return r

    def update_state(self, state=None):
        if not state:
            self.state = [0] * 6
            self.state[:4] = [random.randint(0, N) for _ in range(4)]
            self.state[-2:] = [random.randint(0, 2**N) for _ in range(2)]
        else:
            self.state = state
    
    def reset_state(self):
        self.update_state()

    def digest(self, buffer):
        buffer = int.from_bytes(buffer, byteorder='big')
        m1 = buffer >> N
        m2 = buffer & (2**N - 1)
        self.h = b''
        for i in range(2):
            self.h += int.to_bytes(self.hash_step(i) ^ (m1 if not i else m2), length=N//8, byteorder='big')
        return self.h


def parity(x):
    res = 0
    while x:
        res ^= x & 1
        x >>= 1
    return res


def compute_yc(x):
    import z3
    s = z3.Solver()
    y = z3.BitVec("y", N)
    c = z3.BitVec("c", N)
    s.add((y ^ z3.RotateLeft(y,c)) == x)
    s.check()
    m = s.model()

    return m[y].as_long(), m[c].as_long()

# h = m1 ^ h(0) + m2 ^h(1)
# h(x) = rol(s1, vx1) ^ rol(s2, vx2)

# given x, y is it possible to find:
# s1, s2, r1, r2, r3, r4,
# so that rol(s1, r1) ^ rol(s2, r2) = x
# and     rol(s1, r3) ^ rol(s2, r4) = y
# r1 = 0, r2 = 0, r3 = 0
# x = s1 ^ s2
# rol(s1, r3) ^ rol(s2, r4) = y

# h0 = rol(s1, r1) ^ rol(s2, r2)
# s1 = (h0^y)
# r1, r2 = 0
# s2 = y
# r3 = 0, r4 = c
def solve_round(h1, h2):
    """
    Return r1,r2,r3,r4,s1,s2 such that 
    _ROL_(s1, r1) ^ _ROL(s2, r2) == h1
    _ROL_(s1, r3) ^ _ROL(s2, r4) == h2
    """
    y,c = compute_yc(h1^h2)

    s1 = h1^y
    s2 = y
    r1, r2, r3, r4 = 0, 0, 0, c
    j = 1


    # ensure non-zero vals
    return [r1+j, r2+j, r3+j, (r4+j) % N, _ROR_(s1, j), _ROR_(s2, j)]

r = pwn.remote(sys.argv[1], int(sys.argv[2]))




hashfunc = HashRoll()




ROUNDS = 3

for i in range(ROUNDS):
    r.recvuntil(b"/3!\n")
    l = r.recvuntil(b"\n").decode()
    print(l)


    m = re.search(r'H\(([0-9a-f]+)\) = ([0-9a-f]+)', l)


    message, h = map(lambda x: int(x, 16), m.groups())

    m1 = message >> N
    m2 = message & (2**N - 1)

    th1 = h >> N
    th2 = h & (2**N - 1)

    print(f'H({hex(message)[2:]}) = {hex(h)[2:]}')

    h0 = th1 ^ m1
    h1 = th2 ^ m2

    state = solve_round(h0, h1)
    hashfunc.update_state(state)
    print(hashfunc.digest(message.to_bytes(N, byteorder='big')))
    print(h.to_bytes(2*N//8, byteorder='big'))
    print(hashfunc.digest(message.to_bytes(N, byteorder='big')) == h.to_bytes(2*N//8, byteorder='big'))
    print(state)

    r.recvuntil(b' :: ')

    r.sendline(b','.join(map(lambda x: str(x).encode(), state)))

    print(r.recvline().decode())
print(r.recvline().decode())

    

    # we want hashstep(0) to be m3 ^ m1
    # we want hashstep(1) to be m4 ^ m2